KV6 Intake Manifold Bolts

[Avulon]

Originally Posted by clf

thanks for that Avulon. The link within my last post explained what I was wondering, with a clue from a suggested search in one of Simon's posts. With all the pedantry that was being discussed, I thought it was a good chance to ask lol. Being pedantic about it, would I be correct in thinking that it is mass, since earth's gravity would not be applying the force, but the mass being applied by the operator (ie you when you when you turn the wrench)?

the mass/weight thing was always something that stuck in my mind from school.

The way I understand it.



1kg mass. At 1 earth gravity has a weight of 1kg. Easy .


OK - take away the gravity - 1kg mass weighs nothing - however it's still one kilo of mass.


OK - lets have 0.5 earth gravity - your 1kg of mass now weighs 500g. (it's still one kilo of mass).


Weight is just a way of describing how much force is needed to oppose the influence of gravity on mass. . To take the above example - On earth the one kilo mass requires a table capable of supporting 1kg of weight. In 0.5 Earth gravity the table only need be half as strong.


Now your statement about 'mass applied by the operator' - the operator applies force (of course where's there's gravity this may be by applying their weight on it).


OK. Here's a last bed time puzzler - A one metre bar is being used to turn a 10mm socket using a 1/2" drive. Gravity is 0.5 earth gravity. The bar is perpendicular to the direction of gravitation force and 1kg (mass) is placed on the end. The 10mm socket is turning a machine screw with a an 8mm thread. How much (momentary) torque is being applied (in Nm please)?

[SD1too]

Originally Posted by marinabrian

It's a shame because no one really cares, what matters is whether or not you make yourself understood ...

Only a few days ago Brian you were displaying your pedantry by criticising me for using the term 'bolt' when the item was technically a 'set screw'. Today you take the opposite stance!

Simon

[clf]

Originally Posted by Avulon

The way I understand it.



1kg mass. At 1 earth gravity has a weight of 1kg. Easy .


OK - take away the gravity - 1kg mass weighs nothing - however it's still one kilo of mass.


OK - lets have 0.5 earth gravity - your 1kg of mass now weighs 500g. (it's still one kilo of mass).


Weight is just a way of describing how much force is needed to oppose the influence of gravity on mass. . To take the above example - On earth the one kilo mass requires a table capable of supporting 1kg of weight. In 0.5 Earth gravity the table only need be half as strong.


Now your statement about 'mass applied by the operator' - the operator applies force (of course where's there's gravity this may be by applying their weight on it).


OK. Here's a last bed time puzzler - A one metre bar is being used to turn a 10mm socket using a 1/2" drive. Gravity is 0.5 earth gravity. The bar is perpendicular to the direction of gravitation force and 1kg (mass) is placed on the end. The 10mm socket is turning a machine screw with a an 8mm thread. How much (momentary) torque is being applied (in Nm please)?

5 nm? Believe it or not I 'studied' bending moments during a level, but I failed miserably. Women got in the way lol and the passing of time, little snippets come back, but not necessarily in their right order lol.

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[Avulon]

Originally Posted by clf

5 nm? Believe it or not I 'studied' bending moments during a level, but I failed miserably. Women got in the way lol and the passing of time, little snippets come back, but not necessarily in their right order lol.

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First entry - any other takers?


I guess I'll have to calculate it now as well. ho hum....

[clf]

Originally Posted by Avulon

First entry - any other takers?


I guess I'll have to calculate it now as well. ho hum....

Do we know the type of head on the screw? Or do we assume it to be 6 sided . And assume the threads to be free from swarf and corrosion lol.

I am not even going to look for my scientific calculator, never mind trig tables.

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[Avulon]

Originally Posted by clf

Do we know the type of head on the screw? Or do we assume it to be 6 sided . And assume the threads to be free from swarf and corrosion lol.

I am not even going to look for my scientific calculator, never mind trig tables.

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I was thinking hex-headed.

[clf]

Originally Posted by Avulon

I was thinking hex-headed.

Just doing a bit of reading at this. Not going to find an answer to be honest though. However, what is the material of the screw, and will it be dry or lubricated? If lubricated, what spec the oil lol

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[Avulon]

Originally Posted by clf

Just doing a bit of reading at this. Not going to find an answer to be honest though. However, what is the material of the screw, and will it be dry or lubricated? If lubricated, what spec the oil lol

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Yep, would you like to discuss whether this changes the torque being applied or the torque that should be applied to apply the required clamping pressure of the bolt.....

[marinabrian]

Originally Posted by Mr Logic

Brian

[clf]

Originally Posted by Avulon

Yep, would you like to discuss whether this changes the torque being applied or the torque that should be applied to apply the required clamping pressure of the bolt.....

well............... using sae 30 oil will reduce the torque (effort) required by approx 40% and the clamping pressure is approx 10% if the screw is made from some version of stainless steel ........................................ apparently lol




but that was what I had started to read about earlier (I was in work, and couldnt spend a lot of time reading through it lol) . There was a formula that I am not sure would have been relevant, but when I was using it, with the figures you presented above, I worked it out to be 0.008 Nm of torque. So I think I did it wrong lol (it was an imperial based formula though)